Question Statement:
The determinant of the matrix $M = \begin{bmatrix} 1 & 1 & -1 \\ 2 & 1 & 0 \\ 3 & 1 & 1 \end{bmatrix}$ is:
Step-by-Step Solution & Explanation
### **Detailed Step-by-Step Solution (GATE AE 2018 Q.30 / AE Q.20)**
**1. Intuitive Physical Setup & Given Parameters**:
- Given matrix:
$M = \begin{bmatrix} 1 & 1 & -1 \\ 2 & 1 & 0 \\ 3 & 1 & 1 \end{bmatrix}$
**2. Step-by-Step Mathematical Derivation**:
1. **Evaluating Determinant by Expansion along Row 2**:
Using row 2 ($2, 1, 0$) due to the presence of 0:
$\det(M) = -2 \begin{vmatrix} 1 & -1 \\ 1 & 1 \end{vmatrix} + 1 \begin{vmatrix} 1 & -1 \\ 3 & 1 \end{vmatrix} - 0$
2. **Computing $2 \times 2$ Minors**:
$\begin{vmatrix} 1 & -1 \\ 1 & 1 \end{vmatrix} = (1)(1) - (-1)(1) = 1 + 1 = 2$
$\begin{vmatrix} 1 & -1 \\ 3 & 1 \end{vmatrix} = (1)(1) - (-1)(3) = 1 + 3 = 4$
3. **Combining**:
$\det(M) = -2(2) + 1(4) = -4 + 4 = 0$
4. **Alternative Row Operation Verification**:
Notice that $\text{Row}_3 = 2\text{Row}_2 - \text{Row}_1$:
$2(2, 1, 0) - (1, 1, -1) = (4-1, 2-1, 0 - (-1)) = (3, 1, 1) = \text{Row}_3$
Since Row 3 is a linear combination of Row 1 and Row 2, the rows are linearly dependent, so $\det(M) = 0$.
**3. Comprehensive Options & Distractor Analysis**:
- **Question Type**: Numerical Answer Type (NAT).
- **Exact Evaluation**: **0.0** (Acceptable Range: [0.0, 0.0]).
**4. Official Master Key & Exam Takeaway**:
- **Official Answer**: **0.0**
- **Exam Rule**: Always check for linear dependence between rows before computing full cofactor expansion: if $\sum c_i R_i = 0$, $\det(A) = 0$.
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